Pressure losses of convectors
Pressure losses of convectors
KORAFLEX FK 9/16, FK 11/16, KORABASE 10
KORAFLEX FK 9/20, 9/28, 11/20, 11/28, KORALINE 9/18 a 9/24, KORABASE 20, KORAFLEX FV 8/28, 9/28,11/28, KORAFLEX FV InPool 13/34
KORAFLEX FK 9/34 a 11/34, KORAFLEX FV 11/34, KORABASE 30
KORAFLEX FK 9/42, 11/42, KORAFLEX FV 11/42
KORAFLEX FK 15/28, 19/28, 30/28, 45/28, KORALINE LK 15/18, 30/18, 45/18, 60/18, KORABASE 22
KORAFLEX FK 15/34, 19/34, 30/42, 45/42, KORALINE LK 15/24, 30/24, 45/24, 60/24, KORALINE LD, KORABASE 33
KORAFLEX FK 15/42, 19/42
KORAWALL WK 45/6, 60/6
KORAWALL WK 45/12, 60/12
KORAWALL WI 45/11
KORAFLEX FV 11/20, KORAFLEX FI 11/20
KORAFLEX FI 13/34
KORAFLEX FW 13/34
Examples of conversion to a variant temperature difference
Δt = (tw1 + tw2) / 2 – ti
Where:
tw1 is the inlet water temperature (°C)
tw2 is the outlet water temperature (°C)
ti is the air temperature (°C)
Δt is the cooling of water (K)
The resistance coefficient is valid for both 1/2'' connections. You will find the kt factor in the table of correction factors of the particular element.
Entered:
- KORABASE 22/140 heating element
- Rated operating condition: 75/65/20 °C
- Qn = 1198 W should be converted to the temperature difference Δt = 40 K
- Q = Qn × factor kt = 1198 × 0,748 = 896 W
Entered:
- KORAWALL WK 140/60/6 heating element
- Rated operating condition: 75/65/20 °C
- Qn = 1018 W should be converted to the temperature difference Δt = 30 K
- Q = Qn × factor kt = 1018 × 0,515 = 525 W